Math Quiz: Nicole Heath
- \(x^2+x-20=(x-4)(x+5)\)
- \(10.5(1+r)^{30}\)
- \((6.71\times 10^8)\times (2.3\times 10^{-4})\approx 1.54\times 10^5\)
- \( \pi L(1-\alpha)R^2=4\pi\sigma T^4R^2\)
- \(56 \text{ mi} \times \frac{1.61 \text{ km}}{1 \text{ mi}} ≈ 90 \text{ km}\)
- \[ 56 \text{ mi} \times \frac{ 1.61 \text { km} } {1 \text{ mi} } \approx 90\text{ km}\]
- \($10,000,000 \times (0.98)^{100} \approx $1,300,000. \)
- \(7,681,118,346) \approx 7,700,000,000 = 7.7 \times 10^9\)
- \[150 \text{ m} \times \frac{4.5 \times\ 10^{6} \text{ kg}}{1 \text{ sec}}\times\frac{10 \text{ J}} {1 \text{ kg}\times{1 \text{ m}}} = 6.75 \text{ GW}\]
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