# Daily Archives: February 17, 2016

## Bibliography 2 – Alec West

Topic: I want to talk about how much energy is produced by the Penn State campus and whether it is feasible to produce all that electricity by solar power. I will also examine how many solar panels will be needed … Continue reading

## Math test

1- $$x^3-3x^2-10x=0$$ 2- $$(1+r)^n$$ 3- $$(5.7\times10^{-8})\times(1.6\times10^{12})=9.12\times10^{4}$$ 4- $$\pi\text{L}(1-\alpha)\text{R}^2=4\pi\sigma\text{T}^4\text{R}^2$$ 5- $$12\text {km} \times \frac{0.6\text{mile}}{1\text{km}} \approx 7.2\text{mile}$$ $12\text {km} \times \frac{0.6\text{mile}}{1\text{km}} \approx 7.2\text{mile}$ 6- $$4,173,445,346.50\approx 4,200,000,000=4.2\times 10^{9}$$ 7- $50\text{m}\times \frac{3.4\times 10^{6}\text{kg}}{1\text{sec}}\times \frac{10\text{J}}{1\text {kg}\times 1\text {m}}=1.7\text{GW}$ 8- $$\5,000\times(1+0.012)^{30}\approx \ 7,150$$

## Math Test

$$x^3-3x^2-10x=0$$ $$(1+r)^n$$ $$(5.7\times 10^{-8})\times (1.6\times 10^{12}) = 9.12\times 10^4$$ $${\pi}L(1-\alpha)R^2 = 4{\pi}{\sigma}T^4R^2$$ $12\text{km} \times \frac{0.6 \text{mile}}{1 \text{km}} \approx 7.2 \text{mile}$ $$4,173,445,346.50 \approx 4,200,000,000 = 4.2 \times 10^9$$ $50\text{m} \times \frac{3.4\times 10^6 \text{kg}}{1\text{sec}}\times \frac{10\text{ J}}{1 \text{kg} \cdot 1 \text{m}} = … Continue reading Posted in Uncategorized | Leave a comment 1. $$x^3-3x^2-10x=0$$ 2. $$(1+r)^n$$ 3. $$(5.7\times 10^{-8})\times (1.6\times 10^{12})=9.12\times 10^4$$ 4. $$(\pi)L[1-(\alpha)](R^2)=4(\pi)(\sigma)T^{4}R^2$$ 5. $$12\text{km}\times\frac{0.6\text{mile}}{1\text{km}}\approx 7.2\text{mile}$$ \[12\text{km}\times\frac{0.6\text{mile}}{1\text{km}}\approx 7.2\text{mile}$ 6.  $$4,173,445,346.50 \approx 4,200,000,000 = 4.2\times 10^9$$ 7.  $$50\text{m}\times\frac{3.4\times 10^6\text{kg}}{1\text{sec}}\times \frac{10\text{J}}{1\text{kg}\cdot 1\text{m}}=1.7\text{GW}$$ 8.  $$\5,000\times(1+0.012)^{30}\approx \7,150$$

## Math Test

$$x^3 – 3x^2 – 10x = 0$$ $$(1 + r)^n$$ $$5.7\times 10^{-8}\times 1.6\times 10^{12} = 9.12\times 10^{4}$$ $$\pi L(1-\alpha) R^2 = 4 \pi \sigma T^{4} R^2$$ $$12 \text{ km} \times \frac{ 0.6 \text{ mile}}{1 \text{ km}} \approx 7.2 \text{ mile}$$ … Continue reading

## Math Test

$$x^3-3x^2-10x=0$$ $$(1+r)^n$$ $$(5.7\times10^{-8})\times(1.6\times10^{12})=9.12\times10^4$$ $$\pi L(1-\alpha)R^{2}=4\pi\sigma T^{4}R^{2}$$ $$12km\times\frac{0.6\text{mile}}{1\text{km}}\approx7.2\text{mile}$$ $$4173445246.50\approx4200000000=4.2\times10^{9}$$ $$50m\times\frac{3.4\times10^6\text{kg}}{1\text{sec}}\times\frac{10\text{J}}{1\text{kg}\times1\text{m}}=1.7\text{GW}$$ $$5000\times(1+0.012)^{30}\approx\7150$$

## Math Test

$$x^3-3x^2-10x=0$$ $$(1+r)^n$$ $$(5.7\times10^{-8})\times(1.6\times10^{12})=9.12\times10^4$$ $$\pi L(1-\alpha)R^2=4\pi \sigma T^4R^2$$ $$12\text{ km}\times\frac{0.6{ mile}}{1{ km}}\approx7.2\text{ mile}$$ $12\text{ km}\times\frac{0.6{ mile}}{1{ km}}\approx7.2\text{ mile}$ $$4,173,445,346.50\approx4,200,000,000=4.2\times10^9$$ $50\text{ m}\times\frac{3.4\times10^6\text{ kg}}{1\text{ sec}}\times\frac{10\text{ J}}{1\text{ kg}\times1\text{ m}}=1.7\text{ GW}$ $$\5,000\times(1+0.012)^{30}\approx\7,150$$