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# Daily Archives: February 22, 2016

## Math Test Charles Bramble

\(x^3 – 3x^2 – 10x = 0\) \((1 + r)^n\) \((5.7 \times 10^-8) x (1.6 \times 10^12) = 9.12 \times 10^4\) \(\pi L(1 – \alpha )R^2 = 4\pi \sigma T^4R^2\) \(12 \text{ km} \times \frac{0.6 \text{ mile}}{1 \text{ km}} \approx … Continue reading

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