Math Test Charles Bramble

\(x^3 – 3x^2 – 10x = 0\)

\((1 + r)^n\)

\((5.7 \times 10^-8) x (1.6 \times 10^12) = 9.12 \times 10^4\)

\(\pi L(1 – \alpha )R^2 = 4\pi \sigma T^4R^2\)

\(12 \text{ km} \times \frac{0.6 \text{ mile}}{1 \text{ km}} \approx 7.2\text{ mile}\)

\[12 \text{ km} \times \frac{0.6 \text{ mile}}{1 \text{ km}} \approx 7.2\text{ mile}\]

\(4,173,445,346.50 \approx 4,200,000,000 = 4.2 \times 10^9\)

\[50 \text{ m} \times \frac{3.4 \times 10^6\text{ kg}}{1\text{ sec}} \times \frac{10\text{ J} }{1\text{ kg} \cdot 1\text{ m} } = 1.7\text{ GW} \]

\(\$ 5,000\times (1+0.012)^{30}\approx \$ 7,150.\)

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